Simplification of Radical Expressions - Socratic How do you find the cubed root of 343? What is the cube root of 128? What is the square root of 90? How do you write in simplified radical form of #4sqrt (48)#? How do you simplify #5sqrt (12)+sqrt (75)#? What are the steps for simplifying radicals? How do you write the expression #sqrt (48x^6y^3)# in simplified radical form
How do you simplify the radical expression sqrt72? | Socratic sqrt72 = sqrt (36xx26)=sqrt36xxsqrt2 = 6xxsqrt2 This takes advantage of the relation sqrt (axxb)=sqrtaxxsqrtb Look for a factor in the original value that is a perfect square (4, 9, 16, 25, 36, etc )
Answers created by Rachel - Socratic What is the purpose of hyperbole? How do you write #3sqrt2 + 5sqrt2# in simplified radical form? Can you have 4 right angles in a pentagon? Mario is 15 years older than Pete Two years from now, Mario will be four times as old as Pete How old is each now? How do you combine #sqrt 3 + 2#?
How do you write a polynomial in standard form, then . . . - Socratic This polynomial can be simplified by collecting ' like terms' 5 − 4x2 + 6 − 11x2 = −15x2 +11 This polynomial has 2 terms, −15x2 and+ 11 To express a polynomial in 'standard form' , we start with the highest power of the variable followed by terms with decreasing powers until the last term, usually a constant The polynomial in standard form is −15x2 + 11 The degree of a polynomial is
How do you solve x^2 = 121? - Socratic You take the square root of both sides and make the right side have +- signs Or you can write in standard form and factor Given x^2 = 121 Take the square root of both sides (don't forget the +- on the right): x = +-11 This separates into: x = 11 and x = -11 Another way to do it is: Given x^2 = 121 Write in standard form by subtracting 121 from both sides: x^2-121=0 The form x^2-c always